A) \[8R\]
B) \[9R\]
C) \[10R\]
D) \[20R\]
Correct Answer: B
Solution :
\[g'=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\Rightarrow \frac{g}{100}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] \[{{\left( 1+\frac{h}{R} \right)}^{2}}=100\] \[h=9R\]You need to login to perform this action.
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