A) \[30\sqrt{2}A\]
B) \[60\,\,A\]
C) \[100\,\,A\]
D) \[60\sqrt{2}A\]
Correct Answer: B
Solution :
The impedance of the circuit is \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[{{X}_{L}}=\omega L=400\times 20\times {{10}^{-2}}=8H\] \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{400\times 625\times {{10}^{-6}}}=4F\] \[Z=\sqrt{{{(3)}^{2}}+{{(8-4)}^{2}}}=5\] The peak current in the circuit \[i=\frac{E}{Z}=\frac{300}{5}=60\,\,A\]You need to login to perform this action.
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