A) \[M\]
B) \[M/8\]
C) \[M/0.5\]
D) \[M/2\]
Correct Answer: D
Solution :
\[2{{S}_{2}}O_{3}^{2-}\xrightarrow{{}}{{S}_{4}}O_{6}^{2-}+2{{e}^{-}}\] \[{{E}_{N{{a}_{2}}{{S}_{2}}{{O}_{3}}}}=\frac{2M}{2}=M\]You need to login to perform this action.
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