A) \[(4,\,\,3)\]
B) \[(3,\,\,4)\]
C) \[(4,\,\,-3)\]
D) None of these
Correct Answer: A
Solution :
The equations of the line and hyperbola are \[y=x-1\] ... (i) \[3{{x}^{2}}-4{{y}^{2}}=12\] ... (ii) From Eqs. (i) and (ii), we get \[3{{x}^{2}}-4{{(x-1)}^{2}}=12\] \[\Rightarrow \] \[3{{x}^{2}}-4({{x}^{2}}-2x+1)=12\] or \[{{x}^{2}}-8x+16=0\Rightarrow x=4\] From Eq. (i), \[y=3\] Hence, required point of contact is\[(4,\,\,3)\].You need to login to perform this action.
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