A) \[3\]
B) \[\frac{1}{2\pi }\]
C) \[\frac{\pi }{2}\]
D) \[\frac{1}{\pi }\]
Correct Answer: B
Solution :
\[x=-0.3\sin \left( t+\frac{\pi }{4} \right)\] \[x={{x}_{0}}\sin (\omega t+\phi )\] \[{{x}_{0}}=0.3,\,\,\omega =1\]and\[\phi =\frac{\pi }{4}\] \[2\pi f=1\] \[f=\frac{1}{2\pi }\]You need to login to perform this action.
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