A) \[3\,\,m\]
B) \[15\,\,m\]
C) \[1\,\,m\]
D) \[10\,\,m\]
Correct Answer: D
Solution :
Let \[u\] be the initial velocity and \[h\] be the maximum height attained by the stone \[v_{1}^{2}={{u}^{2}}-2gh\] \[{{(10)}^{2}}={{u}^{2}}-2\times 10\times \frac{h}{2}\] ... (i) Again at height\[h\] \[v_{2}^{2}={{u}^{2}}-2gh\] \[{{(0)}^{2}}={{u}^{2}}-2\times 10\times h\] \[{{u}^{2}}=20h\] ... (ii) So, from Eqs. (i) and (ii), we have \[100=10h\] \[h=10m\]You need to login to perform this action.
You will be redirected in
3 sec