A) \[3.15\]
B) \[1.575\]
C) \[6.30\]
D) \[12.60\]
Correct Answer: C
Solution :
Weight of \[50\,\,mL\] \[\text{of}\,\,1\,\,M\] oxalic-acid \[w=\frac{NEV}{1000}\] \[(\text{Here},\,\,N=m)\] \[=\frac{1\times 126\times 50}{1000}\] \[=6.3\,\,g\] Similarly weight of 50 ml of Q.5 M oxalic acid \[=\frac{0.5\times 126\times 50}{1000}\] \[=3.15\,\,g\] Adsorbed oxalic acid on \[0.5\,\,g\]charcoal\[=6:3-3.15=3.15g\] Amount of oxalic acid adsorbed per gram of charcoal \[=\frac{3.15}{0.5}=6.3\]You need to login to perform this action.
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