A) \[80\]
B) \[60\]
C) \[20\]
D) \[40\]
Correct Answer: C
Solution :
From Raoult's law, relative lowering in vapour pressure \[\Delta p=\frac{{{p}^{o}}-p}{{{p}^{o}}}=\frac{n}{N}=\frac{W}{m}\times \frac{M}{W}\] Here, \[w=12\,\,g;\,\,W=108\,\,g,\,\,m=?\] \[M=18\,\,g,\,\,\Delta p=0.1\] \[\Delta p=\frac{W}{m}\times \frac{M}{W}\] or \[0.1=\frac{12}{m}\times \frac{18}{108}\] \[m=\frac{12\times 18}{10.8}=20\]You need to login to perform this action.
You will be redirected in
3 sec