A)
B)
C)
D) None of these
Correct Answer: C
Solution :
Number of hybrid orbitals = number of\[bp+\]number of\[lp\] \[=5+1=6\] Thus, hybridisation is \[s{{p}^{3}}{{d}^{2}}\] but geometry due to the presence of one lone pair is square pyramidal.You need to login to perform this action.
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