A) \[10,\,\,8\]
B) \[12,\,\,10\]
C) \[12,\,\,8\]
D) \[18,\,\,10\]
Correct Answer: C
Solution :
Since, \[a\]and \[x\] are integers. Therefore,\[(x-a)(x-10)+1=0\] \[\Rightarrow \] \[(x-a)(x-10)=-1\] \[\Rightarrow \] \[(x-a=1\,\,and\,\,x-10=-1)\] or \[(x-a=-1\,\,and\,\,x-10=1)\] \[\Rightarrow \] \[(x=9\,\,and\,\,a=8)\]or\[(x=11\,\,and\,\,a=12)\]You need to login to perform this action.
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