A) \[\frac{r}{4}\]
B) \[\frac{r}{2}\]
C) \[\frac{r}{8}\]
D) \[\frac{r}{16}\]
Correct Answer: B
Solution :
Since, the potential at \[{{A}_{1}}F\] is same. The potential at \[A,\,\,O\] and \[E\] is same. The potential at \[C\] and \[D\] is same. \[\therefore \]The circuit can be reduced to The equivalent resistance of part (i) is \[\frac{1}{{{R}_{1}}}=\frac{1}{r}+\frac{1}{r}+\frac{1}{r}+\frac{1}{r}\] or \[{{R}_{1}}=\frac{r}{4}\] Similarly, \[{{R}_{2}}=\frac{r}{4}\] \[{{R}_{PQ}}={{R}_{1}}+{{R}_{2}}=\frac{r}{2}\]You need to login to perform this action.
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