A) \[g/\sqrt{\mu }\]
B) \[g/\mu \]
C) \[2\mu g\]
D) \[{{\mu }^{2}}g\]
Correct Answer: B
Solution :
Due to frictional force, the block will be prevented from falling. From figure, we have \[N=m{{a}_{0}}\] ... (i) \[f=mg=\mu N\] ... (ii) Solving Eqs. (i) and (ii), we get \[mg=\mu (m{{a}_{0}})\] \[\Rightarrow \] \[{{a}_{0}}=g/\mu \]You need to login to perform this action.
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