A) \[C{{H}_{3}}-CH=NNHCONHC{{H}_{3}}\]
B) \[C{{H}_{3}}-CH=N-OH\]
C) \[C{{H}_{3}}CH=N-NHCON{{H}_{2}}\]
D) \[C{{H}_{3}}-CH=N-NHCONH-CON{{H}_{2}}\]
Correct Answer: C
Solution :
Key Idea: Write reaction to find correct answer \[\underset{\text{acetaldehyde}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H}}\,+\underset{\text{semicarbazide}}{\mathop{{{H}_{2}}NNHCON{{H}_{2}}}}\,\xrightarrow{{}}\] \[\underset{\text{acetaldehyde}\,\text{semicarbazone}}{\mathop{C{{H}_{3}}-\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=NNHCON{{H}_{2}}}}\,\]You need to login to perform this action.
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