A) 3
B) 6
C) 4
D) 1.5
Correct Answer: B
Solution :
\[{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2{{H}^{+}}+SO_{4}^{2-}\] \[\because \]1 mole\[{{H}_{2}}S{{O}_{4}}=2g-\]equivalent of \[{{H}_{2}}S{{O}_{4}}\] \[\therefore \]3 mole \[{{H}_{2}}S{{O}_{4}}=2\times 3g-\]equivalent of \[{{H}_{2}}S{{O}_{4}}\] \[=6g-\]equivalent of \[{{H}_{2}}S{{O}_{4}}\]You need to login to perform this action.
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