A) 1 : 2
B) 4 : 1
C) 1 : 4
D) 2 : 1
Correct Answer: A
Solution :
Frequency of fundamental note in closed pipe is \[n=\frac{v}{4l}\] ?(i) Frequency of fundamental note in open pipe is \[n\,=\frac{v}{2{{l}_{2}}}\] ?(ii) Given, \[n=n\,\] \[\therefore \] \[\frac{v}{4{{l}_{1}}}=\frac{v}{2{{l}_{2}}}\] \[\Rightarrow \] \[{{l}_{2}}:{{l}_{2}}=1:2\] Note: A closed pipe produces only odd harmonics while an open pipe produces both even and odd harmonics.You need to login to perform this action.
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