A) \[F=i\,lB\sin \theta \]
B) \[F={{i}^{2}}l{{B}^{2}}\sin \theta \]
C) \[F=i\,l\,B\,\cos \theta \]
D) \[F=\frac{{{i}^{2}}l}{B}\sin \theta \]
Correct Answer: A
Solution :
The general equation for the force acting on a current carrying conductor placed in a magnetic field [B] is given by Note: The expression can also be obtained from Lorentz force equation.You need to login to perform this action.
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