A) 135.0
B) 172.0
C) 90.0
D) 180.0
Correct Answer: D
Solution :
Key Idea: \[\text{Mole}\,\text{mass}=\,\,\frac{1000\times {{k}_{f}}\times w}{\Delta {{\Tau }_{f}}\times W}\] Given \[{{k}_{f}}=1.86\] \[w=\]mass of solute = 4.5 g \[W=\]mass of solvent \[=100\,g\] \[\Delta {{\Tau }_{f}}=\]Depression in freezing point = 0.465° C \[\therefore \]Molecular weight of solute \[=\frac{100\times 1.86\times 4.5}{0.465\times 100}\] \[=180\]You need to login to perform this action.
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