A) 300 Hz
B) 500 Hz
C) 1000 Hz
D) 400 Hz
Correct Answer: A
Solution :
Key Idea: Beats = Difference in frequencies. The frequency of vibration \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] ?(i) Given, \[n'=n+\frac{3}{2},T'=T+\frac{T}{100}=\frac{101\,T}{100}\] \[\therefore \] \[n+\frac{3}{2}=\frac{1}{2l}\sqrt{\frac{101T}{100\,m}}\] \[\Rightarrow \] \[n+\frac{3}{2}=1.005\times \frac{1}{2l}\sqrt{\frac{T}{m}}\] ?(ii) From Eqs. (i) and (ii),we get \[n+\frac{3}{2}=1.005\times n\] \[\Rightarrow \] \[n=300\,Hz\]You need to login to perform this action.
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