A) exactly at the target
B) 10 cm below the target
C) 10 cm above the target
D) 5 cm above the target
Correct Answer: D
Solution :
We know that distance \[\text{(sd)}\,\text{=}\,\text{speed}\,\text{(v)}\,\text{ }\!\!\times\!\!\text{ }\,\text{time}\,\text{(t)}\] \[\Rightarrow \] \[t=\frac{s}{v}\] Given, \[v=500\,m{{s}^{-1}},s=50\,m\] \[\therefore \] \[t=\frac{50}{500}=0.1\,s\] From equation of motion, for vertical displacement \[h=ut+\frac{1}{2}g{{t}^{2}}\] Given, \[u=0,t=0.1\,s\] \[\therefore \] \[h=\frac{1}{2}\times 10\times {{(0.1)}^{2}}=0.05\,m=5\,cm.\] Hence, the rifle must be aimed 5 cm above the target.You need to login to perform this action.
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