A) \[5\sqrt{2}\,m/s\]
B) \[2\sqrt{5}\,m/s\]
C) \[3\sqrt{5}\,m/s\]
D) \[5\sqrt{3}\,m/s\]
Correct Answer: D
Solution :
Key Idea: Maximum velocity at lowest point is V5 times maximum velocity at highest point. Diameter AB of circle is 3m Therefore, radius \[r=\frac{3}{2}m\] velocity at \[A(v)=\sqrt{5gr}\] Given, \[g=10\,m/{{s}^{2}},r=\frac{3}{2}m\] \[\therefore \]\[v=\sqrt{5\times 10\times \frac{3}{2}}=5\sqrt{3}\,m/s\]You need to login to perform this action.
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