A) \[4\cos \theta \]
B) \[4(2cos\theta -sec\theta )\]
C) \[(2cos\theta +4sec\theta )\]
D) \[4(sec\theta +cos\theta )\]
Correct Answer: B
Solution :
Key Idea: Horizontal component of velocity remains same. Let \[v\]be the velocity, when projected with angle \[\theta ,\] then equating the horizontal velocities in both the cases, we getYou need to login to perform this action.
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