A) 50% D + 50% L-isomer
B) 20% D + 80% L-isomer
C) D-isomer
D) L-isomer
Correct Answer: A
Solution :
Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exists as d and \[l\] forms whose ratio is 1:1. \[\underset{50%\,\text{L}-\text{isomer}}{\mathop{H-\underset{CN}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH}}\,\,\,\,\,\,+\,\,\,\,\,\,\underset{50%\,D\,-\text{isomer}}{\mathop{HO-\underset{CN}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H}}\,\]You need to login to perform this action.
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