A) \[{{30}^{0}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{0}^{o}}\]
Correct Answer: C
Solution :
Key Idea Slope of the path of the particle gives the measure of angle required. Draw the situation as shown. OA represents the path of the particle starting from origin O(0,0). Draw a perpendicular from point A to \[x-\]axis. Let path of the particle makes an angle \[\theta \]with the \[x-\]axis, then \[\tan \theta =\text{slope}\,\text{of}\,\text{line}\,\text{oA}\] \[=\frac{OA}{OB}=\frac{3}{\sqrt{3}}=\sqrt{3}\] or \[\theta ={{60}^{o}}\]You need to login to perform this action.
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