A) 0.1%
B) 1%
C) 0.2%
D) 0.8%
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[{{T}^{2}}=4{{\pi }^{2}}\frac{l}{g}\] \[\Rightarrow \] \[g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\] Here % error in \[l=\frac{1\,mm}{100\,cm}\times 100=\frac{0.1}{100}\times 100=0.1%\] and \[%\]error in \[T=\frac{0.1}{2\times 100}\times 100=0.05%\] \[\therefore \]\[%\]error in \[g=%\,\,\text{error}\,\text{in}\,l+2(%\,\text{error}\,\text{in}\,\text{T})\] \[=0.1+2\times 0.05\] \[=0.2%\]You need to login to perform this action.
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