A) \[+250\,kJ\]
B) \[-250\,kJ\]
C) \[+125\,kJ\]
D) \[-125\,kJ\]
Correct Answer: D
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}\xrightarrow{{}}C{{H}_{3}}-C{{H}_{3}}\] \[\Delta \Eta ={{(BE)}_{\text{reactants}}}-{{(BE)}_{\text{products}}}\] \[=4{{(BE)}_{C-H}}+{{(BE)}_{C=C}}+{{(BE)}_{H-H}}\] \[-[6{{(BE)}_{C-H}}+{{(BE)}_{C-C}}]\] \[=-125\,kJ\]You need to login to perform this action.
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