A) 0.04
B) 0.01
C) 1
D) 5
Correct Answer: A
Solution :
The given equation is \[y=5\sin \frac{\pi }{2}(100t-x)\] ?(i) Comparing Eq. (i) with standard wave equation, given by \[y=A\sin (\omega t-kx)\] ?(ii) we have \[\omega =\frac{100\pi }{2}=50\pi \] \[\Rightarrow \] \[\frac{2\pi }{T}=50\pi \] \[\Rightarrow \] \[T=\frac{2\pi }{50\pi }=0.04\,s\]You need to login to perform this action.
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