A) \[10\,m\Omega \]resistance is to be connected in parallel to the galvanometer
B) \[10\,m\Omega \] resistance is to be connected in series with the galvanometer
C) \[0.1\,\Omega \]resistance is to be connected in parallel to the galvanometer
D) \[0.1\,\Omega \]resistance is to be connected in series with the galvanometer
Correct Answer: A
Solution :
To convert a galvanometer into an ammeter, a shunt resistance in parallel is connected to galvanoiraeter. Since, galvanometer G and shunt S are in parallel, hence \[{{i}_{g}}G=(i-{{i}_{g}})\] \[\Rightarrow \] \[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\] \[=\frac{4\times {{10}^{-3}}\times 15}{6-4\times {{10}^{-3}}}\] \[=\frac{60\times {{10}^{-3}}}{5.996}\] \[=10\times {{10}^{-3}}\,\Omega \] \[=10\,m\Omega \]You need to login to perform this action.
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