To get an output 1 from the circuit shown in the figure, the input must be
A) \[A=0,B=1,C=0\]
B) \[A=1,B=0,C=0\]
C) \[A=1,B=0,C=1\]
D) \[A=1,B=1,C=0\]
Correct Answer:
C
Solution :
We can realize the gate circuit as Output of gate \[1,{{Y}_{1}}=A+B\] Output of gate\[1,{{Y}_{2}}={{Y}_{1}}.C\] \[=(A+B).C\] If \[A=0,B=1,C=0,\]then \[{{Y}_{2}}=(0+1).0=1.0=0\] If \[A=1,B=0,C=0,\]then \[{{Y}_{2}}=(1+0).0=1.0=0\] If \[A=1,B=0,C=1,\]then \[{{Y}_{2}}=(1+0).1=1.1=1\] If \[A=I,B=1,C=0,\]then \[{{Y}_{2}}=(1+1).0=1.0=0\]