A) \[~-900\,J\]
B) \[~-\,900\,kJ\]
C) 270 kJ
D) 900 Kj
Correct Answer: A
Solution :
Work done due to change in volume against constant pressure, \[W=-p({{V}_{2}}-{{V}_{1}})\] \[=-1\times {{10}^{5}}N{{m}^{-2}}(1\times {{10}^{-2}}-1\times {{10}^{-3}}){{m}^{3}}\] \[=-900Nm=-900\,J\]\[(1\,Nm=1J)\]You need to login to perform this action.
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