• question_answer A solution contains 10 mL 0.1 N NaOH and $\text{10}\,\text{mL}\,\text{0}\text{.05}\,\text{N}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{,pH}$of this solution is A)  less than 7       B)  7 C)  zero             D)  greater than 7

Solution :

Given, for $NaOH,V=10mL,N=0.1N$ For ${{H}_{2}}S{{O}_{4}},V=10\,mL,\,N=0.05\,N$ Miliequivalents of$NaOH=10\times 0.1=1$ Miliequivalents of ${{H}_{2}}S{{O}_{4}}=10\times 0.05=0.5$ $\underset{1\,\text{equivalent}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+\underset{\text{2}\,\text{equivalent}}{\mathop{2NaOH}}\,\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O$ $\because$ 0.5 equivalent of ${{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}$will react with 1 equivalent of $\text{NaOH}$ $\therefore$ The pH of solution = 7 (neutral)

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