A) 5 fermi
B) 6 fermi
C) 11.16 fermi
D) 8 fermi
Correct Answer: C
Solution :
We have, \[r\propto {{A}^{1/3}}\] \[\Rightarrow \] \[\frac{{{r}_{2}}}{{{r}_{1}}}={{\left[ \frac{{{A}_{2}}}{{{A}_{1}}} \right]}^{1/3}}\] \[={{\left[ \frac{206}{4} \right]}^{1/3}}\] \[\ \therefore \] \[{{r}_{2}}=3{{\left[ \frac{206}{4} \right]}^{1/3}}=11.16\,\text{fermi}\]You need to login to perform this action.
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