A) \[{{60}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{30}^{o}}\]
D) None of these
Correct Answer: A
Solution :
For a given prism, the angle of deviation depends upon the angle of incidence of the light rays falling on the prism. Taking triangle FQR, we have \[S=\angle FQR+\angle FRQ\] Since,\[\Delta AQR\] is an equilateral triangle, therefore, \[\angle FQR=\frac{{{60}^{o}}}{2}={{30}^{o}}=\angle FRQ\] \[\therefore \] \[\delta ={{30}^{o}}+{{30}^{o}}={{60}^{o}}\] Hence, angle of deviation of the ray is \[{{60}^{o}}.\]You need to login to perform this action.
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