A) 0.1 M
B) 0.001 M
C) 0.01 M
D) \[{{10}^{-4}}\,M\]
Correct Answer: B
Solution :
Molarity of \[\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]solution \[=\frac{2.65}{106}\times \frac{1}{250}\times 1000=0.1\,M\] \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] \[10\times 0.1=1000\times {{M}_{2}}\] \[\therefore \] \[{{M}_{2}}=\frac{10\times 0.1}{1000}=0.001\,M\]You need to login to perform this action.
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