A) 36kW
B) 18 kW
C) 45kW
D) 54kW
Correct Answer: C
Solution :
Power required for rotar, \[P=\tau .\,W\] \[=36\,kW\] Power of engine \[{{P}_{0}}=\frac{P}{0.8}=45\,kW\]You need to login to perform this action.
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