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JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    short bar magnet placed with its axis- at \[{{30}^{o}}\] with a uniform external magnetic field of 0.16 T experience a torque of magnitude 0.032 J. The magnetic moment of the bar magnet will be

    A)  \[0.23\,J{{T}^{-1}}\]

    B)  \[0.40\,J{{T}^{-1}}\]

    C)  \[0.80\,J{{T}^{-1}}\]

    D)  zero

    Correct Answer: B

    Solution :

     Magnetic moment \[M=\frac{T}{B\sin \theta }=\frac{0.032}{0.16\times \sin {{30}^{o}}}\] \[=0.40\,J/T\]


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