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JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4m, its kinetic energy would be

    A) \[10\,J\]

    B)  \[20\,J\]

    C)  \[40\,J\]

    D)  \[50\,J\]

    Correct Answer: A

    Solution :

     Initial kinetic energy of the body \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 25\times {{(2)}^{2}}=50\,J\] Work done against resistive force = Area between \[F-x\]graph \[=\frac{1}{2}\times 4\times 20=40\,J\] Final KE = Initial KE - work done against resistive force \[=50-40=10\,J\]


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