A) \[\left( \frac{n-1}{n} \right)f\]
B) \[\left( \frac{n+1}{n} \right)f\]
C) \[(n+1)f\]
D) \[(n-1)f\]
Correct Answer: D
Solution :
Given magnification, \[m=\frac{1}{n}\] So, \[\frac{1}{n}=-\frac{v}{u}\] or \[v=-\frac{u}{n}\] By using mirror formula,\[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\] \[=\frac{1}{-u/n}+\frac{1}{u}\] \[\Rightarrow \] \[u=-(n-1)f\]You need to login to perform this action.
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