A) \[10\,J\]
B) \[20\,J\]
C) \[40\,J\]
D) \[50\,J\]
Correct Answer: A
Solution :
Initial kinetic energy of the body \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 25\times {{(2)}^{2}}=50\,J\] Work done against resistive force = Area between \[F-x\]graph \[=\frac{1}{2}\times 4\times 20=40\,J\] Final KE = Initial KE - work done against resistive force \[=50-40=10\,J\]You need to login to perform this action.
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