A) 2
B) 4
C) 5
D) None of the above
Correct Answer: A
Solution :
Maximum energy is liberated for transition \[{{E}_{n}}\to 1\]and minimum energy for \[{{E}_{n}}\to {{E}_{n-1}}\] Hence, \[\frac{{{E}_{1}}}{{{n}^{2}}}-{{E}_{1}}=52.224\,eV\] ?(i) and \[\frac{{{E}_{1}}}{{{n}^{2}}}-\frac{E}{{{(n-1)}^{2}}}=1.224\,eV\] ?(ii) Solving Eqs. (i) and (ii), we get \[{{E}_{1}}=-54.4\,eV\] and \[n=5\] But \[{{E}_{1}}=-\frac{13.6{{Z}^{2}}}{{{1}^{2}}}\] \[\therefore \] \[-54.4=\frac{13.6}{{{1}^{2}}}{{Z}^{2}}\] \[\Rightarrow \] \[Z=2\]You need to login to perform this action.
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