A) \[2.0\,m{{s}^{-2}}\]
B) \[2.5\,m{{s}^{-2}}\]
C) \[3.0\,m{{s}^{2}}\]
D) \[4.0\,m{{s}^{-2}}\]
Correct Answer: A
Solution :
The maximum weight which can be suspended with the rope without breaking it \[\text{=}\,\text{30}\,\text{kg}\,\text{wt}\text{.}\] \[=30\times 10=300\,N\] \[\therefore \] \[300\,N=mg+ma\] or \[ma=300-mg=300-25\times 10=50N\] or \[a=\frac{50}{m}=\frac{50}{2.5}=2.0\,m{{s}^{-2}}\]You need to login to perform this action.
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