A) equal on both
B) zero on both
C) on the surface of sphere A
D) on the surface of sphere B
Correct Answer: C
Solution :
When the spheres are connected by a wire, then potential on both becomes equal. \[\therefore \] \[\frac{{{Q}_{1}}}{{{r}_{1}}}=\frac{{{Q}_{2}}}{{{r}_{2}}}\]\[\Rightarrow \]\[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\] When \[{{r}_{1}}>{{r}_{2}},\]then \[{{Q}_{1}}>{{Q}_{2}}\]You need to login to perform this action.
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