A) \[-\,41\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
B) \[-1312\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
C) \[-164\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
D) \[-82\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]
Correct Answer: D
Solution :
The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\]is\[-328\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\] therefore \[-328=\frac{E}{{{2}^{2}}}\Rightarrow E=-328\times 4\] \[=-1312\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\] \[\therefore \] \[{{E}_{n}}=\frac{-1312}{{{n}^{2}}}\,kJ\,mo{{l}^{-1}}\] If \[n=4,\] \[\therefore \] \[{{E}_{4}}=-\frac{1312}{{{4}^{2}}}kJ\,mo{{l}^{-1}}\] \[=-82\,kJ\,mo{{l}^{-1}}\]
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