A) \[\frac{Ma}{(g+a)}\]
B) \[\frac{2Ma}{(g+a)}\]
C) \[\frac{M}{(g+a)}\]
D) Not possible
Correct Answer: B
Solution :
Let the retarding force acting on the balloon in vertically upward direction be F. When the balloon is descending down with acceleration a, its equation of motion can be given as \[~Ma=Mg-F\] or \[F=Mg-Ma\] ?(i) Let M mass is removed from the balloon. When it moves up with acceleration a, its equation of motion can be given as \[(M-m)a=F-(M-m)g\] From Eq. (i) \[Ma-ma=Mg-Ma-Mg+mg\] \[\Rightarrow \] \[m=\frac{2Ma}{(g+a)}\]You need to login to perform this action.
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