A) 60 cm
B) 50 cm
C) 30 cm
D) 20 cm
Correct Answer: B
Solution :
The given situation can be shown as Here,\[u=OC=-30\,cm\] \[f=20\,cm\] By using \[\frac{1}{v}=\frac{1}{f}+\frac{1}{u}\] \[=\frac{1}{20}-\frac{1}{30}\] \[=\frac{1}{60}\] \[\Rightarrow \] \[v=60\,cm\] To obtain upright image of O at O itself \[v=O{{C}_{1}}=x+10\] \[\Rightarrow \] \[x=v-10\] \[=60-10=50\,cm\]You need to login to perform this action.
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