A) \[mg\]
B) \[\sqrt{mg}\]
C) Infinite
D) zero
Correct Answer: C
Solution :
The given situation can be shown as from figure \[2T\,\sin \theta =mg\] or \[T=\frac{mg}{2\sin \theta }\] when rope is straight, \[\,\theta ={{0}^{o}}\] \[\therefore \] \[T=\frac{mg}{2\sin \theta }=\infty \] (infinite)You need to login to perform this action.
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