A) \[3\mu C\]
B) \[6\mu C\]
C) \[12\mu C\]
D) \[24\mu C\]
Correct Answer: B
Solution :
From figure it is clear that, current will flow only through the branch containing \[{{R}_{2}}.\] \[\therefore \] \[I=\frac{E}{{{R}_{2}}+r}\] \[=\frac{5}{4+1}\] \[=1\,A\] So, potential difference across\[{{R}_{2}};\] \[V=I{{R}_{2}}\] \[=1\times 4\] \[=4\,V\] Let q be the charge on each plate of each capacitor, then \[\frac{q}{C}+\frac{q}{C}=4\] \[\Rightarrow \] \[\frac{2q}{C}=4\] \[q=2\times C\] \[=2\times 3\] \[=6\,\mu C\]
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