A) \[~1.80\,V\]
B) \[~1.07\,V\]
C) \[0.82\,V\]
D) \[2.14\,V\]
Correct Answer: B
Solution :
\[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{n}\log \left( \frac{Z{{n}^{2+}}}{C{{u}^{2+}}} \right)\] \[=1.10-\frac{0.0591}{2}\log \frac{1}{0.1}\] \[=1.07\,V\]You need to login to perform this action.
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