A) Colour change is due to charge transfer
B) It has iron in+1 oxidation state and nitrosyl as \[\text{N}{{\text{O}}^{+}}.\]
C) It has magnetic moment of 3.87 BM confirming three unpaired electrons in Fe
D) All the above are correct statements
Correct Answer: D
Solution :
\[\left. \begin{align} & NO\xrightarrow{{}}N{{O}^{+}}+{{e}^{-}} \\ & F{{e}^{2+}}+{{e}^{-}}\xrightarrow{{}}F{{e}^{+}} \\ \end{align} \right]\]Charge transfer \[\therefore \] Number of unpaired electron, \[n=3\] \[n=3\]Magnetic moment\[\mu =\sqrt{n(n+2)}\] \[=\sqrt{3(3+2)}\] \[=3.87\,BM\] Thus, all the given options are correct.You need to login to perform this action.
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