A) QR
B) 9R
C) 10R
D) 20R
Correct Answer: B
Solution :
\[g=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\]\[\Rightarrow \]\[\frac{g}{100}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] \[{{\left( 1+\frac{h}{R} \right)}^{2}}=100\] \[h=9R\]You need to login to perform this action.
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