A) \[[{{M}^{0}}L{{T}^{-1}}]\]
B) \[[M{{L}^{0}}{{T}^{-1}}]\]
C) \[[M{{L}^{-1}}{{T}^{0}}]\]
D) \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]
Correct Answer: C
Solution :
\[v=\frac{p}{2l}{{\left[ \frac{F}{m} \right]}^{1/2}}\] Squaring the equation on either side, we have \[{{v}^{2}}=\frac{{{p}^{2}}}{4{{l}^{2}}}\left( \frac{F}{m} \right)\] \[m=\frac{{{P}^{2}}F}{4{{l}^{2}}{{v}^{2}}}\] \[[m]=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}]{{[{{T}^{-1}}]}^{2}}}=[M{{L}^{-1}}{{T}^{0}}]\]You need to login to perform this action.
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